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1/x-3+1/x+3=1/x^2-9
We move all terms to the left:
1/x-3+1/x+3-(1/x^2-9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x^2-9)!=0We add all the numbers together, and all the variables
x∈R
1/x+1/x-(1/x^2-9)=0
We get rid of parentheses
1/x+1/x-1/x^2+9=0
We calculate fractions
We do not support expression: x^3
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